John Carpenter signs on to write a Joker comic

Just when you thought you’d had enough Joker, DC announces they have signed a deal with filmmaker John Carpenter to be the scribe on a Joker comic for their Year of the Villain event. Joining him writing is Anthony Burch (Big Trouble in Little China Old Man Jack), with Philip Tan (Green Lanter, Hawkman, MTG), and Marc Deering (Superman/Batman, Supergirl) providing the visuals.

The Joker is the greatest villain in comics, I’m proud to be reunited with Anthony on this project.

John Carpenter, in the official press release.

The official synopsis from the DC Press Release reads:

Now a human-alien hybrid, Lex Luthor has made his appeal to the world, asking its citizens to embrace doom and give in once and for all to evil, humanity’s true nature. In exchange, he will grant them the tools to ascend to their ultimate selves. While some DC villains (and heroes) are willing to hear what “Apex Lex” has to offer, the Clown Prince of Crime isn’t going to wait around until Lex gets to him. This puts The Joker on a mission to get his swagger back in a world gone bad by out-badding everyone else, proving that the greatest evil is always the one that leaves them laughing.

I’m excited beyond words to be writing for Gotham’s greatest villain, I hope the Joker’s exploits make you laugh, shudder, and grow nauseous all at once.

Anthony Burch, in the official press release.

THE JOKER: YEAR OF THE VILLAIN is a 40-page one-shot priced at $4.99 and debuts in comic book stores and online retailers on Wednesday, October 9.

Do you plan on picking this up? What do you think about DC bringing in a legendary filmmaker into the mix to write about the clown prince of crime? I asked our internal Spoiler-Verse and our reviewer/blogger Jay had this to say.

Do you agree? Disagree? I do agree that some time off from Joker would be nice, however you can’t have “year of the villains” without him. Though an event like this without Joker would make his return that much cooler.

See full press release here:

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